y^2-64y+999=0

Solution for y^2-64y+999=0 equation:

y^2-64y+999=0

a = 1; b = -64; c = +999;
Δ = b2-4ac
Δ = -642-4·1·999
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-10}{2*1}=\frac{54}{2}
=27
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+10}{2*1}=\frac{74}{2}
=37
$